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Q.

An electric field is expressed as E→=2i^+3j^. Find the potential difference (VA−VB) between two points A and B whose position vectors are given by rA=i^+2j^ and rB=2i^+j^+3k^.

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a

-1 V

b

1 V

c

2 V

d

3 V

answer is A.

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Detailed Solution

VB−VA=−∫122dx+∫213dy=−[2(2−1)+3(1−2)]=−[2−3]=1 VHence, VA−VB=−1 V

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An electric field is expressed as E→=2i^+3j^. Find the potential difference (VA−VB) between two points A and B whose position vectors are given by rA=i^+2j^ and rB=2i^+j^+3k^.