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Q.

The electric field intensity at the center of a uniformly charged hemispherical shell is Eo. Now two portions of the hemisphere are cut from either side, and the remaining portion is shown in figure. If α=β=π/3, , then the electric field intensity at the center due to the remaining portion is

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a

E0/3

b

E0/6

c

E0/2

d

information insufficient

answer is C.

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Detailed Solution

The magnitude of electric field intensity due to each part of the hemispherical surface at the center 'O' is same. Suppose it is EE+E2+E2=E0or 2E=E0or E=E02

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