Q.

The electric field of plane electromagnetic wave of amplitude  2V/m varies with time, propagating along  z-axis. The average energy density of magnetic field  in J/m3  is equal to  x×10−12 J/m3. Then ‘x’  value is equal to (∈0=8.854×10−12 F/m)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 8.85.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For an electro magnetic wave ,Average energy density due to electric field=Average energy density due to magnetic field=14ε0E02=14×8.85×10−12×2×2=8.85×10−12 Joule m−3=x×10−12 Joule m−3 ∴x=8.85
Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Online Course for IIT JEE
Best Online Course for NEET
Best Online Course for CBSE
whats app icon
The electric field of plane electromagnetic wave of amplitude  2V/m varies with time, propagating along  z-axis. The average energy density of magnetic field  in J/m3  is equal to  x×10−12 J/m3. Then ‘x’  value is equal to (∈0=8.854×10−12 F/m)