The electric field of a plane electromagnetic wave propagating along the x direction in vacuum is E→=E0j^cosωt−kx. The magnetic field B→, at the moment t = 0 is
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a
B→=E0μ0∈0coskxk^
b
B→=E0μ0∈0coskxj^
c
B→=E0μ0∈0coskxj^
d
B→=E0μ0∈0coskxk^
answer is A.
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Detailed Solution
Amplitude of magnetic field B0=E0C B0=E0μ0ε0E→×B→ is along direction of propagation∴j^×B^ must be parallel to i^ ∴B→ should be along k^ E→,B→ are in same phase∴B→=B0k^cosωt−kx B→=E0μ0ε0cosωt−kxk^ At t = 0 B→=E0μ0ε0coskx k^
The electric field of a plane electromagnetic wave propagating along the x direction in vacuum is E→=E0j^cosωt−kx. The magnetic field B→, at the moment t = 0 is