First slide

Electrostatic Potential

Question

Electric field and potential at a point due to a point charge are 100 v/m and 0.5 volt respectively. Then distance of the point from the point charge is

Moderate

A

2 cm
B

0.1 cm
C

5 cm
D

5 mm

Solution

$\begin{array}{l} E = \frac{1}{4 {πε}_{0}} \frac{Q}{r^{2}} and V = \frac{1}{4 {πε}_{0}} \frac{Q}{r} \\ ∴ r = \frac{V}{E} = \frac{0 .5}{100} m = 5 mm \end{array}$

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