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Q.

The electric field in a region is given by E→=35E0i^+45E0j^  with E0=2×103 N/C . Find the flux of this field through a rectangular surface of area 0.2m2 parallel to y−z  plane in N−m2C−1

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Detailed Solution

E→=352×103i^+452×103j^ =1200i^+1600j^ A→=0.2i^m2 Flux  φ=E→.A→ =1200i^+1600j^.0.2i^ =240 N−m2/C
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