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Electric field in a region is given by E→=−4xi^+6yj^. The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by α∈0. The value of α is ______.

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answer is 2.

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Detailed Solution

ϕ=(6y) Area −(4x) Area =6×1×(1)2−4×1×(1)2=2 therefore qε0=2⇒q=2ε0

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Electric field in a region is given by E→=−4xi^+6yj^. The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by α∈0. The value of α is ______.