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By Expert Faculty of Sri Chaitanya
Question

An electric field of  1000V/m is applied to an electric dipole at angle of 45o . The value of electric dipole moment is 1029C.m . What is the potential energy of the electric dipole?

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Solution

                                                      U=P.E =PEcosθ =10291000cos450 =0.707×1026 =7×1027J


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