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Q.

An electric field of 1000 V/m is applied to an electric dipole at an angle of 45∘. The value of electric dipole moment is 10-29C.m. The potential energy (in joule) of the electric dipole is −7×10−p. Find the value of p.

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answer is 27.00.

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Detailed Solution

Potential energy of a dipole is given by ​U=−​=−PEcosθ​ [Where θ= angle between dipole and field]​⇒U=−(10−29)(103)cos45∘​=−0.707×10−26J​=−7×10−27J
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