An electric field of 1000 V/m is applied to an electric dipole at an angle of 45∘. The value of electric dipole moment is 10-29C.m. The potential energy (in joule) of the electric dipole is −7×10−p. Find the value of p.

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answer is 27.00.

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Detailed Solution

Potential energy of a dipole is given by U=−=−PEcosθ [Where θ= angle between dipole and field]⇒U=−(10−29)(103)cos45∘=−0.707×10−26J=−7×10−27J

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