First slide

Gauss's law and its applications

Question

The electric flux from a cube of edge l is $ϕ$ . If an edge of the cube is made 2l and the charge enclosed is halved, its value will be

Easy

A

4 $ϕ$
B

2 $ϕ$
C

$ϕ$ /2
D

$ϕ$

Solution

$\begin{array}{l} ϕ = \frac{q}{ε_{0}} (Independent of dimensions) \\ \Rightarrow ϕ \propto q \\ New flux, ϕ' = \frac{ϕ}{2} \end{array}$

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