An electric motor operates on a 50 volt supply and a current of 12A. If the efficiency of the motor is 30%, what is the resistance of the winding of the motor?

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6Ω

4Ω

2.9 Ω

3.1Ω

answer is C.

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Detailed Solution

η=eE×100⇒e=0.3E Now, i=E−eR⇒12=50−(0.3×50)R⇒R=2.9Ω

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