An electric motor operating on a 60 V dc supply draws a current of 10 A. If the efficiency of the motor is 50%, the resistance of its winding is
3Ω
6Ω
15Ω
30Ω
Efficiency η=50% So e=E/2
and i=E−eR⇒i=E−E/2R=E2R
⇒R=E2i=602×10=3Ω