The electric potential decreases uniformly from 120 V to 80 V as one moves on the x-axis from x=−1 cm to x=+1 cm. The electric field at the origin

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must be equal to 20 Vcm−1

must be equal to 20 Vm−1

may be greater than 20 Vcm−1

may be less than 20 Vcm−1

answer is C.

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Detailed Solution

Ex=dVdx=120−802=20 Vcm−1There may be the y- and z-components of field also

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