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Q.

Electric potential at a distance of 5 cm from the surface of a charged metallic sphere of radius 10 cm is 10 V. Then the work done by an external agent in slowly moving a +5 μC charge from that point to the surface of the sphere is

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a

30 μJ

b

25 μJ

c

15 μJ

d

60 μJ

answer is B.

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Detailed Solution

If R be the radius of the sphere, then KQR+R2=V⇒KQR=3V2∴V' = Potential at the surface of the sphere =KQR=3V2∴W=Q(V'-V)=Q3V2-V=QV2=5 x 102 μJ=25 μJ

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