The electric potential in a region along the X-axis varies with x according to the relation V (x) = 4 + 5 x2 Then

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potential difference between the points x = 1 and x = -2 is 15 volt

forced experienced by one coulomb charge at x= - 1 m will be 10 N

the force experienced by the above charge will be towards + X-axis

a uniform electric field exists in this region along the x-axis

answer is A.

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Detailed Solution

Given that V˙(x)=4+5x2When x=1, V(1)=9 volt When x=−2, V(−2)=24 volt ∴ ΔV=V(−2)−V(1)=15 volt E=−ΔVΔx=−10x E at x=−1m will be −10×(−1)=+10N/C∴ F=qE=+(1)(10)=+10N along positive x-axis.

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