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The electric potential at the surface of an atomic nucleus (Z = 50) of radius $9 .0 \times 10^{- 13}$ cm is

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80 volts

8×106 volts

9 volts

9×105 volts

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detailed solution

Correct option is B

V=9×109×50×1.6×10−199×10−15=8×106V

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The electric potential at the surface of an atomic nucleus (Z = 50) of radius 9.0×10−13cm is

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The electric potential at the surface of an atomic nucleus (Z = 50) of radius $9 .0 \times 10^{- 13}$ cm is