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The electric potential V is given as a function of distance x by V=(5x2+10x−9) volt. Value of electric field (in V/m) at x=1 m is

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answer is -20.00.

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Detailed Solution

E=−dVdx⇒E=−ddx(5x2+10x−9)=−(10x+10)⇒E=−(10×1+10)=−20 V/m

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