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The electric potential V is given as a function of distance x (metre) by $V = (5 x^{2} + 10 x - 9) volt$ . Value of electric field at x = 1 is

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detailed solution

Correct option is A

E=−dVdx=−ddx5x2+10x−9=−10x−10∴(E)x=1=−10×1−10=−20V/m

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The electric potential V is given as a function of distance x (metre) by V=5x2+10x−9 volt . Value of electric field at x = 1 is

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Ready to Test Your Skills?

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The electric potential V is given as a function of distance x (metre) by $V = (5 x^{2} + 10 x - 9) volt$ . Value of electric field at x = 1 is