Questions
The electric potential V is given as a function of distance x (metre) by V=(5x2 + 10x - 9) volt . Value of electric field at x = 1 is
detailed solution
Correct option is A
E=-dVdx=-ddx5x2+10x-9=-10x-10 ∴(E)x=1=-10×1-10=-20 V/mTalk to our academic expert!
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Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10-15 kg and charge 10-11 C enters in it with a velocity 107 m/s. The acceleration of the particle will be
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