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The electric potential V is given as a function of distance x (metre) by volt. Then electric field at is
detailed solution
Correct option is A
V=9+10x−2x2V∴ E→=−dVdxi^=−10−4xi^=−10−4×1i^ Vm=−6 i^ VmTalk to our academic expert!
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Two parallel plates separated by a distance of 5 mm are kept at a potential difference of 50 V. A particle of mass 10-15 kg and charge 10-11 C enters in it with a velocity 107 m/s. The acceleration of the particle will be
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