Q.

In the electrical circuit shown in the figure, the current i through the side AB is :

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a

1033A

b

15A

c

1063A

d

625A

answer is D.

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Detailed Solution

The current drawn from battery I=1010+3+20  ×  3050  =  1025  Ai  :  I−i   =  3   :  2i=35   I    =   35  ×   1025  =  625  A
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