In the electrical circuit shown in the figure, the current i through the side AB is :

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1033A

15A

1063A

625A

answer is D.

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Detailed Solution

The current drawn from battery I=1010+3+20 × 3050 = 1025 Ai : I−i = 3 : 2i=35 I = 35 × 1025 = 625 A

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