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An electro magnetic radiation whose electric field constant is given by E=Eo(cos 16π×1014t +sin 3.6π×1015 t) V/m is incident on the surface of lithium in on photoelectric experiment. If work function of lithium is 2.39 eV, the maximum kinetic energy of photo electron is

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a

4.16 eV

b

5.06 eV

c

2.39 eV

d

1.24 eV

answer is B.

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Detailed Solution

Kinetic energy of photoelectron will be maximum for the light having frequency 3.6π ×10152πHz in 18×1014 Hz. Energy of photon for this light hv=6.625×10-34×18×10141.6×10-19ev=7.45ev ∴(KE)max=hv-ϕ=(7.45-2.39)ev=5.06ev

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