In an electrolyte 3.2 × 1018 bivalent positive ions drift to the right per second while 3.6 × 1018 monovalent negative ions drift to the left per second. Then the current is
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a
1.6 A to the left
b
1.6 A to the right
c
0.45 A to the right
d
0.45 A to the left
answer is B.
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Detailed Solution
Net current inet = i+ + i−= n+q+t + n−q−t=n+t ×2e+ n−t×e=3.2 × 1018 × 2 × 1.6 × 10−19 +3.6 × 1018 ×1.6 × 10−191.6 A (towards right)