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Electromagnetic radiation having time varying electric field $E = E_{0} (1 + \cos ω t) \cos ω_{0} t$ falls on a metal surface of work function $ϕ$ . If $ω > ω_{0}$ , the possible speed(s) of photoelectron is ( $ℏ (ω - ω_{0}) > ϕ > ℏ ω_{0}$ where $(ℏ = \frac{h}{2 π})$ )

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2ℏω−ϕm

2mℏω+ω0−ϕ

2mℏω0−ϕ

2mℏω−ω0−ϕ

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detailed solution

Correct option is A

E=E0(1+cos⁡ωt)cos⁡ω0t=E0cos⁡ω0t+E02cos⁡ω+ω0t+E02cos⁡ω−ω0t∴Kmax=ħω+ω0−ϕ⇒Vmax=2mħω+ω0−ϕAs per question,ℏω−ω0>ϕ⇒ℏω−ϕ>ℏω0Since,ω0 is positive ⇒ ℏω−ϕ is also positive.

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Electromagnetic radiation having time varying electric field E=E01+cosωtcosω0t falls on a metal surface of work function ϕ. If ω>ω0, the possible speed(s) of photoelectron is (ℏω−ω0>ϕ>ℏω0 where ℏ=h2π)

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Electromagnetic radiation having time varying electric field $E = E_{0} (1 + \cos ω t) \cos ω_{0} t$ falls on a metal surface of work function $ϕ$ . If $ω > ω_{0}$ , the possible speed(s) of photoelectron is ( $ℏ (ω - ω_{0}) > ϕ > ℏ ω_{0}$ where $(ℏ = \frac{h}{2 π})$ )