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An electromagnetic wave of frequency $1 \times 10^{14}$ hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If $ε_{0} = 8.8 \times 10^{- 12} C^{2} / N - m^{2}$ , then average energy density of electric field will be:

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35.2×10-10 J/m3

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detailed solution

Correct option is C

Given: Amplitude of electric field, E0=4v/m Absolute permitivity, ε0=8.8×10-12c2/N-m2 Average energy density uF=? Applying formula, Average energy density uE=14ε0E2 ⇒ uE=14×8.8×10-12×(4)2 =35.2×10-12 J/m3

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An electromagnetic wave of frequency 1×1014 hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If ε0=8.8×10-12C2/N-m2, then average energy density of electric field will be:

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An electromagnetic wave of frequency $1 \times 10^{14}$ hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If $ε_{0} = 8.8 \times 10^{- 12} C^{2} / N - m^{2}$ , then average energy density of electric field will be: