Q.

An electromagnetic wave of frequency 1×1014 hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If ε0=8.8×10-12C2/N-m2, then average energy density of electric field will be:

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

35.2×10-10 J/m3

b

35.2×10-11 J/m3

c

35.2×10-12 J/m3

d

35.2×10-13 J/m3

answer is C.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Given: Amplitude of electric field,  E0=4v/m  Absolute permitivity,  ε0=8.8×10-12c2/N-m2  Average energy density uF=?  Applying formula,   Average energy density uE=14ε0E2 ⇒  uE=14×8.8×10-12×(4)2 =35.2×10-12 J/m3
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
An electromagnetic wave of frequency 1×1014 hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If ε0=8.8×10-12C2/N-m2, then average energy density of electric field will be: