First slide

Nature of electromagnetic wave

Question

An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity $ε_{r} = 4 .0 .$ Then

Moderate

A

wavelength is doubled and the frequency remains unchanged
B

wavelength is doubled and frequency becomes half
C

wavelength is halved and frequency remains unchanged
D

wavelength and frequency both remain unchanged

Solution

Refractive index $= \sqrt{\frac{με}{μ_{0} ε_{0}}}$
Here $μ$ is not specified so we can consider $μ = μ_{0},$ then
Refractive index $= \sqrt{\frac{ε}{ε_{0}}} = 2$
Hence, speed and wavelength of wave becomes half and frequency remains unchanged.

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