An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity εr=4.0. Then
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
wavelength is doubled and the frequency remains unchanged
b
wavelength is doubled and frequency becomes half
c
wavelength is halved and frequency remains unchanged
d
wavelength and frequency both remain unchanged
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Refractive index =μεμ0ε0Here μ is not specified so we can consider μ=μ0, then Refractive index =εε0=2Hence, speed and wavelength of wave becomes half and frequency remains unchanged.