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An Intiative by Sri Chaitanya
a
B→x, t=9 x 10-8T j^ sin1.5 x 10-6x-2 x 1014t
b
B→x, t=3 x 10-8T j^ sin1.0 x 106x-3 x 1014t
c
B→x, t=9 x 10-8T j^ sin1.5 x 10-8x-3 x 1014t
d
B→x, t=9 x 10-8T k^ sin2π1.0 x 106x-3 x 1014t
answer is D.
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