In an electromagnetic wave in vacuum, the electric and magnetic fields are 40πV/m and 0.4×10−7T. The poynting vector is

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4.4 Wm−2

0.44 Wm−2

5.65 Wm−2

4.0 Wm−2

answer is D.

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Detailed Solution

Poynting vector is S→=E→×B→μ0Magnitude of Poynting vector is S=EBμ0 [E→ and B→ are perpendicular to each other] ⇒S=40π×0.4×10−74π×10−7=4.0 Wm−2

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