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Motion of a charged particle

Question

An electron is accelerated from rest through a potential difference V. This electron experiences a force F in a uniform magnetic field. On increasing the potential difference to V’,the force experienced by the electron in the same magnetic field becomes 2F. Then, the ratio (V’/V) is equal to

Moderate
Solution

K=12mv2=eV   or v=2eVm  Also, F=evB=e2eVm×B  Therefore, F2F=V1V2=VV'   V'V=41



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