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An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) me=9×10-31 kg

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a
12.2nm
b
12.2×10-13 m
c
12.2×10-12 m
d
12.2×10-14 m

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detailed solution

Correct option is C

de Broglie wavelength of electron, λe=12.27 AV(inV)  Here, V=10000 V ∴ λe=12.2710000×10-10 m=12.27×10-12 m

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