First slide
Matter waves (DC Broglie waves)
Question

An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) me=9×10-31 kg

Easy
Solution

 de Broglie wavelength of electron, λe=12.27 AV(inV)  Here, V=10000 V  λe=12.2710000×10-10 m=12.27×10-12 m

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