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An electron is accelerated through a potential difference of 10,000 volt and its de-Broglie wavelength is found to be λ. What will be the de-Broglie wavelength of an electron when accelerated through a potential difference of 40,000 volt?

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Detailed Solution

K.E of electron =p22m∴p22m=eV⇒p=2meV∴λ=hp=h2meV⇒λ∝1V⇒λ'λ=10,00040,000=12⇒λ'=λ2

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