First slide

Force on a charged particle moving in a magnetic field

Question

An electron accelerated through a potential difference y enters into a uniform transverse magnetic field and experiences a force F. If the accelerating potential increases to 2V, the electron in the same magnetic field will experience a force :

Easy

A

F
B

F/2
C

$\sqrt{2} F$
D

2F

Solution

$\frac{1}{2} {mv}^{2} = eV or V = (2 eV / m)^{1 / 2}$
Force F = $evB = eB (2 eV / m)^{1 / 2} or F \propto \sqrt{V}$
When V is doubled, then F' = $\sqrt{2} \cdot F$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App