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Questions  

An electron beam moves undeflected in a Lorentz Field given by σ .Then the velocity of electron beam is 

a
1.5×104j^(m/s)
b
6×104j^(m/s)
c
3×105−j^(m/s)
d
1.5×105−j^(m/s)

detailed solution

Correct option is B

Lorentz force F→ = −eV→ ×B→ +−eE→ = 0(−e)V →× B →+(−e)E→=0⇒(vxi^+vyj^+vzk^)×(0.5k^)=(3×104)i^⇒0.5×vy×(i^)=(3×104)i^⇒vy=6×104m/s∴V→=6×104j^m/s

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