Questions
As the electron in Bohr orbit of hydrogen atom passes from state n = 2 to n = 1, the KE (K) and PE (U) change as :
detailed solution
Correct option is B
→-PE.U∝1n2 ; →+KE∝1n2 ∴-U1-U2=n2n12 ; ∴K1K2=n2n12 ∴UU1=122 ∴KK1=122 ∴U1=4U ; ∴K1=4KTalk to our academic expert!
Similar Questions
In a H atom, let K, n be the kinetic energy of the electron and principal quantum number, respectively. Now, relate K, n according to Bohr's model of H atom:
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests