As the electron in Bohr orbit of hydrogen atom passes from state n = 2 to n = 1, the KE (K) and PE (U) change as :

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K two-fold, U also two-fold

K four-fold, U also four-fold

K four-fold, U two-fold

K two-fold, U four-fold

answer is B.

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Detailed Solution

→-PE.U∝1n2 ; →+KE∝1n2 ∴-U1-U2=n2n12 ; ∴K1K2=n2n12 ∴UU1=122 ∴KK1=122 ∴U1=4U ; ∴K1=4K

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