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As the electron in Bohr orbit of hydrogen atom passes from state n = 2 to n = 1, the KE (K) and PE (U) change as :

a
K two-fold, U also two-fold
b
K four-fold, U also four-fold
c
K four-fold, U two-fold
d
K two-fold, U four-fold

detailed solution

Correct option is B

→-PE.U∝1n2 ; →+KE∝1n2 ∴-U1-U2=n2n12 ; ∴K1K2=n2n12  ∴UU1=122  ∴KK1=122 ∴U1=4U ; ∴K1=4K

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In a H atom, let K, n be the kinetic energy of the electron and principal quantum number, respectively. Now, relate K, n according to Bohr's model of H atom:


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