First slide
Magnetic field due to a current carrying circular ring
Question

An electron of charge e moves in a circular orbit of radius r around a nucleus. The magnetic field due to orbital motion of the electron at the site of the nucleus is B. The angular velocity ω of the electron is

Moderate
Solution

The electron moving in a circular orbit is equivalent to a current carrying loop. If v be its frequency, then

i=ve=e/T (T= time period )
We know that T=(2πr/v)
 i=ev2πr=e()2πr=2π
                    (where ω = angular frequency)
The magnetic field at the centre of the loop
B=μ0i2r
or B=μ02r2π=μ04πr
           ω=4πrBμ0e

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