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Q.

An electron, a doubly ionized helium ion He++  and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths λe,λHe++ and λp  is:

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a

λe <λP <  λHe++

b

λe >λHe++ >  λP

c

λe >λP >  λHe++

d

λe <λHe++ =  λP

answer is C.

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Detailed Solution

λ=h2Km​⇒λ∝1m​λe:  λHe++: λp=1me:1mHe:1mp   ​⇒λe>  λp> λHe++
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