First slide

Electrostatic potential

Question

An electron enters between two horizontal plates separated by 2 mm and having a potential difference of 1000 V. The force on electron is

Easy

A

8 x 10^-12N
B

8 x 10^-14N
C

8 x 10^-9N
D

8 x 10¹⁴N

Solution

Force on electron, F= QE = $Q (\frac{V}{d})$
$\Rightarrow F = (1.6 \times 10^{- 19}) (\frac{1000}{2 \times 10^{- 3}}) = 8 \times 10^{- 14} N$

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