Q.
An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of the electron in this state is Pπa0 (where a0 is the Bohr radius). The value of P is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Bohr's Postulate ,nh2π=3h2π⇒n=3Radius=r=a0n2z⇒r=a093=3a0Wavelength=λ=hmv=hrmvr=hrnh2π=2πrn⇒λ=2π3a03 ⇒λ=2πa0So, P=2
Watch 3-min video & get full concept clarity