Q.

An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be

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a

1.7×10−11 N/C

b

5.0×10−11 N/C

c

5.5×10−11 N/C

d

56 N/C

answer is C.

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Detailed Solution

E=Fq=mge=9×10−31×9.81.6×10−19=5.5×10−11N/C
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