Q.
An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be
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a
1.7×10−11 N/C
b
5.0×10−11 N/C
c
5.5×10−11 N/C
d
56 N/C
answer is C.
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Detailed Solution
E=Fq=mge=9×10−31×9.81.6×10−19=5.5×10−11N/C
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