First slide

Electric field

Question

An electron falls through a small distance in a uniform electric field of magnitude 2 x 10⁴ NC^-1. The direction of the field is reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

Easy

A

same in both cases
B

more in the case of an electron
C

more in the case of proton
D

independent of charge

Solution

The time required to fall through distance d is
$S = u t + \frac{1}{2} a t^{2} \Rightarrow d = \frac{1}{2} (\frac{q E}{m}) t^{2} or t = \sqrt{\frac{2 d m}{q E}}$
Since $t^{2} \propto m,$ a proton takes more time.

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