An electron having kinetic energy K is moving in a circular orbit of radius R perpendicular to a uniform magnetic induction B. If kinetic energy is doubled and magnetic induction tripled, the radius will be
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a
3R2
b
32R
c
29R
d
43R
answer is C.
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Detailed Solution
Radius of circle = R=mVBq=2mKBq New radius =R1=2m(2K)(3B)q=292mKBq =29 R