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An electron in a hydrogen atom undergoes a transition from an orbit with quantum number ni to another with quantum number nf .Vi and Vf are respectively the initial and final potential energies of the electrons. If ViVf=6.25, then the smallest possible nf is

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answer is 5.

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Detailed Solution

Potential energy =−27.2n2in eVVi=−27.2ni2 and Vf=−27.2nf2⇒ViVf=nf2ni2=6.25 (given)⇒nfni=2.5 for ni=2nf=5(smallest possible value)

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An electron in a hydrogen atom undergoes a transition from an orbit with quantum number ni to another with quantum number nf .Vi and Vf are respectively the initial and final potential energies of the electrons. If ViVf=6.25, then the smallest possible nf is