An electron in hydrogen-like atom makes a transition from nth orbit and emits radiation corresponding to Lyman series. If de-Broglie wavelength of electron in nth orbit is equal to the wavelength of radiation emitted, find the value of n. The atomic number of atom is 11.
If A is de-Broglie wavelength, then for nth stationary orbit
where rn is radius of nth orbit.
For Lyman series of hydrogen like atom, wavelength is given as,
From Eqs. ) and (i),
Rydberg constant,
Substituting given values, we get
As negative n is not possible,
Alternative solution : Energy of emitted photon =
=
Solving n = 25
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