An electron is launched with velocity v→ in a uniform magnetic field B→. The angle θ between V→and B→lies between 0 and π2. Its velocity vector v→ returns to its initial value in a time interval of
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a
2πmeB
b
2×2πmeB
c
πmeB
d
depends upon angle between v→ and B→
answer is A.
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Detailed Solution
Time interval in which v→ returns to its initial value is same as time period of the particle, hence the required time =2πmeB
An electron is launched with velocity v→ in a uniform magnetic field B→. The angle θ between V→and B→lies between 0 and π2. Its velocity vector v→ returns to its initial value in a time interval of