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An electron mass  =  9.1×1031  kg,  charge=1.6×1019  C experiences no deflection if subjected to an electric field of 3.2×105  V/m and a magnetic fields of 0.2 μT  Both the fields are normal to the path of electron and to each other. If the electric field is removed, then the electron will revolve in an orbit of radius

a
45 m
b
4.5 m
c
0.45 m
d
0.045 m

detailed solution

Correct option is C

For no deflection in mutually perpendicular electric an magnetic field, v=  EB= 3.2  ×  1030.2=1.6  ×  104   m/s.If electric field is removed, then due to only magnetic field, radius of the path described by electron isr=  mvqB= 9.1  ×  10−31 ×1.6  ×  104  1.6  ×  10−19 ×0.2 ×10-6=0.45 m

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