An electron of mass m moving with initial velocity v→=v0i^+v0j^ is in an electric field E→=−E0k^. If λ0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
λ01+e2E02t2m2v02
b
λ01+e2E2t22m2v02
c
λ02+e2E2t2m2v02
d
λ021+e2E2t2m2v02
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Electric force on electron due to the electric field is,F→=ma→=eE→For velocity, using vf=u+at⇒v→f=v0i^+v0j^+−eE0mtk^vf→=2v02+e2E2m2t2Now applying equation for de-broglie wavelength,λ=hm2v02+e2E02m2t2λ=λ01+e2E022m2v02t2