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Q.

An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is: (c being the velocity of light)

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a

1cE2m12

b

E2m12

c

c2mE12

d

1c2mE12

answer is A.

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Detailed Solution

Wave length of photon =λph=hcE ∵E=hcλ Wave length of electron λe=hp Here p=2Em ∴λe=h2Emλeλph=h2EmhcE=Ec2Em⇒λeλph=E2m⋅1c=1cE2m1/2
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