Questions
An electron of mass and a photon have same energy . The ratio of de-Broglie wavelengths associated with them is
a
C(2mE)12
b
1c2mE12
c
1cE2m12
d
E2m12(c being velocity of light)
detailed solution
Correct option is C
For electron of energy E de-Broglie wavelength, λe=hp=h2mEFor photon of energy,E=hv=hcλp⇒λp=hcE∴λeλp=h2mE×Ehc=1cE2m1/2Talk to our academic expert!
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An electron is orbiting in 4th energy state in a hydrogen atom. The de-Broglie wavelength associated with this electron is nearly equal to
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