An electron(of mass m) and a photon have some energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c=speed of light in vacuum)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1cE2m12
b
1c2Em12
c
c2mE12
d
E2m12
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
de-Broglie wavelength for electron =λd =h2mE Wavelength of photon=λ=hcERatio λdλ=h2mE×Ehc=1cE2m