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Q.

An electron of mass m whet accelerated through a potential difference V has de-Broglie wavelength λ The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

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a

λmM

b

λmM

c

λMm

d

λMm

answer is B.

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Detailed Solution

Momentum of electrons Pe=2meVMomentum for  proton Pp=2MeVλpλe=hPphPe=PePp=2meV2MeV λpλe=mM λp=λemM∴(λe=λ) λp=λmM
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